C programming output

Question

Q. Consider the C program shown below

#include <stdio.h>

#define print (a) printf (“%d”, a)

int a;

void A (int p)

{

            p+ = a;

            print (p);

}

void B(int *q)

{

            int p = *q + 3;

            A (a);

            *q = a – 2;

            print  (a);

            }

Main (void)

{

            a = 6;

            B(&a);

            print(a);

}

The output of this program is

(a) 15, 7, 6                                                                   (b) 15, 7, 7

(c) 13, 7, 6                                                                   (d) 13, 7, 7

Comments

None of the option looks correct. What i'm getting is 12, 4, 4.

Answer 1

output of this code is 12 4 4  i think something correction in options.

first  call the function B

without changing the value of a we call to A so print -->12

return to function B

change the value a=6-2=4;

print value of a--->4

return in main function

print value of a-->4

Answer 2

OPTION A)IS CORRECT IF WE MODIFY THE CODE AS

#include <stdio.h>

#define print (a) printf (“%d”, a)

int a;

void A (int p)

{

            p+ = a;

            print (p);

}

void B(int *q)

{

            int p = *q + 3;

            A (p);

            *q = p – 2;

            print  (*q);

            }

Main (void)

{

            a = 6;

            B(&a);

            print(a);

}

The output of this program is

Answer 3

I am getting 12,4,4 some changes need to be done in options/in question......you please check ones both

Answer 4

None of the above option is true.

Output is : 12 4 4