792 views

1 Answer

Best answer
1 1 vote

very nice problem... 

If N = ap * bq * cr ... 
Number of factors = (p + 1)*(q + 1)*(r + 1)....

We are given number of factors = 8
=> (p + 1)*(q + 1)*(r + 1).... = 8

So the possibilities for splitting 8 are 8, 2*4, 2*2*2
so here number could be of the format a7, a*b3, a*b*c
a7 format
The smallest odd number of this format is 37. That is not a two digit number. 

a*b3 format
The smallest odd number of this format is 5*33. That is not a two digit number. 

a*b*c format
The smallest odd number of this format is 3*5*7. That is not a two digit number. 

So, there is no odd two digit number that has 8 factors.

• selected by
Position:
Show:

Related questions

2 2 votes
1 answers 1 answer
1.2k
1.2k views
akankshadewangan24 asked Jun 28, 2017
1,243 views
how many numbers less than 1000 will have exactly 3 factor?
0 0 votes
0 0 answers
360
360 views
Misbah Ghaya asked Aug 26, 2022
360 views
Please list out the best free available video playlist for Factors from Quantitative Aptitude as an answer here (only one playlist per answer). We'll then select the best...
0 0 votes
1 1 answer
436
436 views
Shubham Sharma 2 asked Jun 16, 2025
436 views
How many distinct factors does $2^{2} 3^{3} 4^{4} 5^{5}$ have? For example, $12$ has $6$ distinct fact ors: $1,2,3,4,6$, and $12$.$240$$264$$324$$360$None of the above