Switch case

Question

Output of the following program?

#include <stdio.h>

char input[ ] = "SSSWILTECH1\1\11W\1WALLMP1";

main() {

int  i,c;

for( i=2 ; ( c=input[i] ) ! = '\0' ; i++) {

switch(c) {

case 'a' : putchar( 'i' );continue;

case '1' : break;

case 1 : while( ( c=input[++i] )!= '\1' && c!= '\0' );

case 9 : putchar( 'S' );

case 'E' :

case 'L' : continue;

default : putchar (c);

continue;

}

putchar( ' ' );

}

putchar( '\n' );

}

Comments

Answer given-- SWITCH  SWAMP .

Answer 1

        #include <stdio.h>
        char input[ ] = "SSSWILTECH1\1\11W\1WALLMP1";
        int main(void) {
        	int i,c;
            for(i=2;(c=input[i])!='\0';i++){//Printing starts at a[2]
            switch(c) {
            case 'a' : putchar( 'i' );continue;
            case '1' : break;
            case 1 : while( ( c=input[++i] )!= '\1' && c!= '\0' );
            case 9 : putchar( 'S' );
            case 'E' :
            case 'L' : continue;
           default : putchar (c);
           continue;
            }
			putchar( ' ' );
			}
			putchar( '\n' );
        	return 0;
        }

Printing starts at a[2]=S, and case S is by default print S. 'L' and 'E' executes continue statements.

Comments

After reading first '1' it will break and come out of the switch statement and then execute putchar(' '); ryt?

But what will happen when at '\'  ?