Can you please also let me know the Link utilisation in this case?
I think the formula is %LU = (Throughput/Bandwidth)*100 right? I am getting 0.049 which is not matching any options that i have.
The options are
a) 0.0005 b) 0.0002 c) 0.0001 d) 0.0050
dont get confused by the terms...here by transmission rate means the throughput of system= datasize / total time
100 / (TT+ 2PT)
TT=data size / bandwidth
= 100/ 100000= 1ms=0.001 sec
2PT=round trip time=2 sec
transmission rate= 100/(2+0.001) = 49.97 bps
this means even the bandwidth provided is 100000 bps, but we can transmit with the rate of 49.97 bps.