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I strongly suggest that all answers here are wrong and interpreted the question very wrongfully..
@Arjun@Bikram@Manu Thakur
in a relationship in ER model with n relations participating together we NEVER TAKE 2 RELATIONS AT A TIME AND SAY 1:m or 1:1 etc..
THE RULE IS TAKE (n-1) at a time with the other one..
so here AB and C; BC and A;AC and B are only 3 categories of saying whether they are x:y (x,y ∈ {1,m} ) .
YOU CAN'T JUST INVENT A 1:M OR WHATEVER RELATIONSHIP BETWEEN ONLY 2 OF THEM...THIS INTERPRETATION IS NOT CORRECT.
TO DO THAT FIRST CONVERT IT TO SOME DUAL RELATIONSHIP MODELS WHICH IS OF NO NEED HERE.
for A,B,C its m,1,1 given in diagram
meaning..
stmt_1)for one pair of A,B there can be at most 1 C
stmt_2)for one pair of A,C there can be at most 1 B
stmt_3)for one pair of B,C there can be at most m A's
so, A,B->C ; A,C->B
******we can never know if A->B , A->C, B->C , C->B holds or not.*******
here Candidate keys are both A,B and A,C
and A,B,C is a strict superkey.
now, this two fd together never indicates B->C or C->B
A1,B1,C1
A2,B1,C1
A3,B1,C2
all can be in R
EVEN IF THEY DID, THAT DOES NOT MEAN THAT YOU STATE A RELATIONSHIP ONLY BETWEEN 2 OF THEM DIRECTLY.
IN A STATEMENT DICTATING RELATIONSHIP, 3 RELATIONS MUST BE THERE IF YOU'RE INTERCEPTING TERNARY RELATIONSHIP.
now the very fact that both AB and AC are candidate keys in turn makes each of A,B & C a prime attribute.
so none of them can contain NULL value.
now it asks for maximum number of triples in R,
so answer must be 100*min(1000,10)=1000