Programming and Data Structure

Question

What is the output of following program

#include<stdio.h>

int main()
{
    short int i=20;
    char c=97;
    printf("%d,%d,%d\n",sizeof(i),sizeof(c),sizeof(c+i));
    return 0;
}

(A)2,1,2

(B)2,1,1

(C)2,1,4

(D)2,2,8

Comments

it should be a)

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how u get 4 as output?

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Useful Read: https://stackoverflow.com/questions/24371868/why-must-a-short-be-converted-to-an-int-before-arithmetic-operations-in-c-and-c

Answer 1

how sizeof(c+i)= 4  ???

Comments

See this: https://stackoverflow.com/questions/24371868/why-must-a-short-be-converted-to-an-int-before-arithmetic-operations-in-c-and-c

Answer 2

On most systems: sizeof(short int) = 2  So first output = 2

sizeof(c) c is a char.sizeof(char) = 1

In an arithmetic expression, C applies integer promotion rules:

• char and short are promoted to int before the operation.