Computer Networks Switching

Question

A packet switching network (highly loaded) has the following characteristics:
Propagation delay = 2sec/hop
Data Transmission rate = 1 Mbps
Packet size = r bit = 512 bits
Number of hops = 10
At what time the last bit of the last packet will reach the receiver?

Answer is 1025sec

How is this Question solved?

Comments

i think answer is wrong because

TT=L/B=512/1000000

PT=20

total will be 20 +0.000512 sec

Answer 1

i think...time taken by receiver to receive a packet:-

T_t+T_p+T_t+T_p+T_t+T_p.........+T_t+T_{p ...}{10.T_t+10.T_p}

and T_t=512bits/10⁶bps Tp=2sec....????   {Tt=transmission delay Tp=propagation delay}

Comments

http://www.avatto.com/computer-science/test/networking/questions/3521/discuss
 

See according to your solution answer would be 20sec+512*10^(-5)sec  which is not equal to 1250sec
 

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@shaurya uppal

@hs_yadav has done correct(assuming there is only one packet), actually qsn is incomlete, it has not mentioned number of packets, and in qsn it is asking

"At what time the last bit of the last packet will reach the receiver?"

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One thing I would like you to do, copy the entire question and paste it on google you will see the same question in many places with 1025sec as answer but you won't find solution to this.
Question is absolutely correct.