For a channel of 3 KHz bandwidth and signal to noise ratio of 30 dB, the maximum data rate is:
(A) 3000 bps (B) 6000 bps
(C) 15000 bps (D) 30000 bps
From my point of view shannon's theorem is c=B*log2(1+SNR)
so it's 3*10^3*log2 (1+30) = so it's nearest to 3*10^3 * 5 = 15000 bps.. so answer is "C".
Correct if i'm wrong
Applying Shannon's Theorem we get answer as D
C) 151000 bps