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2 Answers

2 votes
2 votes

Easy way to understand.. We are not actually taking the intersection part but we are omitting the intersection so that we have union of all super keys possible.. I hope you understand 

1 votes
1 votes

44 is the answer a2^5+bc2^4+cd2^4-abc2^3-acd2^3-bcd2^3+abcd2^2

32+32-8-8-8+4

68-24

44

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