Pointers

Question

Answer given is D "gh" . how??

Comments

t=p=*(p+2-1)

That is *(p+1)

i.e cd

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Size of int is given 2 bytes. why did u take 4 here??

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@chandra sai , I am getting the same answer while computing in IDE but there they are taking value of sizeof(int) as 4. But in this question it is given as 2. So i think answer should be different(i.e. option B).

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I also marked B option. But given was D

What is the conclusion now about this type of  question?

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@atul_21, I will be sticking to my solution until someone gives better explanation.

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@harish thanks for pointing out . now corrected.

formerly i assumed default value of int

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If we take size of int as 2 then answer is cd

If we take size of int as 4 the answer is gh

Answer 1

old compilers the size of integer is 2bytes and new compilers the size of integer is 4B.

 If nothing is mention in the question about size of a integer then consider size of int is 4B.if they mention we have to consider that value.

Here size of int is 2B.

char *t;

t=(p+=sizeof(int))[-1] 

t=(p+2)[-1]   // p+2 it skips 2 positions from start.and p is pointing to array position 2.

p[-1] again it goes back then p points to p[1].

print all characters in that string and output is cd.

So option should be B.

Suppose if we execute this programme on new compilers it gives 'gh' as outpot.