ace test series

Question

E-->TE/a

T-->ET/b

first set of E and T??

Comments

First(E) = First(T) = {a, b}

---

yes First of both are {a,b}

Answer 1

First(E) = {a, b}

First(T) = {a, b}

Answer 2

• $first (E)=first(T)\cup first(a)=(a,b)$
• $first(T)=first(E) \cup first(b)=(a,b)$