Option must be option D.
Explanation :
initially F is pointing to node with value 1.
Step 1 : P = F->link->link->link->link
F->link = 1->link =2
(F->link)->link = 2->link =3
(F->link->link)->link = 3->link = 4
(F->link->link->link)->link = 4->link =5 (Hence P is poinitng at node with value =5)
Step 2 : P->link->link = F->link->link
We are assigning value of (F->link)->link to P->link->link
F->link = 1->link = 2
(F->link)->link = 2->link =3.
Now, P->link = 6
P->link->link = 6->link = null.
Hence last null value will now points to node with value 3.
Step 3 : F->link = p->link
already we have computed p->link .
Hence F->link = 6.(Simple 1st node now point to 6 directly instead of 2).
Printing :
p->data = 5.
F->link->link->link->link->data = 1->6->3->4->5 (data of node 5) = 5
P->link->link->link->link->data = 5->6->3->4->5 (data of node 5) = 5.
