0 votes 0 votes Kaluti asked Dec 24, 2017 Kaluti 317 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply joshi_nitish commented Dec 24, 2017 reply Follow Share 280 ?? 1 votes 1 votes Ashwin Kulkarni commented Dec 24, 2017 i reshown by Ashwin Kulkarni Dec 24, 2017 reply Follow Share Haha i forget that * 8 :p Yes its 280 0 votes 0 votes Ashwin Kulkarni commented Dec 24, 2017 reply Follow Share HLEN value = 10 (It is normalised value hence actual header length = 10*4 = 40) Hence msg length = 1500-40 = 1460. Off set is stored in normalised form hence offset value = 100*8 = 800 . now MTU is 200 hence msg length in MTU = 160. Now 160 is already in multiple of 8 hence no need to change in data length. Hence there will be 1460/160 = 9.. Hence before last packet 9 packets will be there. (total 10) 1st packet : offset = 100, msg length =160 2nd packet : offset = 100 + 160/8 = 120 3rd packet : offset = 120 + 160/8 = 140 .. .. .. 9th packet = 240+160/20 = 260 10th last packet = 260 + 160/20 = 280. 3 votes 3 votes Please log in or register to add a comment.