test series

Question

Comments

If it had been pre-increment, then what you are saying would have been true. Steps involved in both the types are shown:

(fun--)

Step1: fun(n);

Step2:n=n-1;

Because of the 1st step, function can never be called for the decremented value of n

But,

fun(--n)

Step1:n=n-1;

Step2:fun(n);

Can you see the difference now...

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thanks.....got it now!

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Similar question: https://gateoverflow.in/183214/c-prog

Answer 1

5

4

3

2

1

Comments

@Deeksha, this is post-decrement,hence would give infinite loop, see the comments below the other answer