Output of printf

Question

What is the output???

Comments

no problem, if we print in different line

rt?

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@srestha  why it is printing 0 in printf("%f %f\n",a,4/2) for second %f ?

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printf in separate lines prints 2.0 2.0 and on the same line prints 2.0 0.0

:O How

Answer 1

For the statement: printf("%f,%f\n",a,4/2);

Answer would be 2.000000,0.000000

Refer to https://stackoverflow.com/questions/11673503/using-f-to-print-an-integer-variable where you can find this:

printf's "%f" format expects an argument of type double, and prints it in decimal form with no exponent. Very small values will be printed as 0.000000.

When you do this:

int x=10;
printf("%f", x);

we can explain the visible behavior given a few assumptions about the platform you're on:

• int is 4 bytes
• double is 8 bytes
• int and double arguments are passed to printf using the same mechanism, probably on the stack

So the call will (plausibly) push the int value 10 onto the stack as a 4-byte quantity, and printf will grab 8 bytes of data off the stack and treat it as the representation of a double. 4 bytes will be the representation of 10 (in hex, 0x0000000a); the other 4 bytes will be garbage, quite likely zero. The garbage could be either the high-order or low-order 4 bytes of the 8-byte quantity. (Or anything else; remember that the behavior is undefined.)

Comments

4/2 is 0 in int? how

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so sorry @gauravkc, had given the explanation for modulus!! edited the answer accordingly.. thanks :)

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why double taking for 1st line but not for 2nd line?

https://ideone.com/AXQrpS

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Have you explain for modules or division explain again