ascii print code

Question

printf("The ASCII value of %c = %d\n",i,i);   what is the meaning of this line  why i,i written in the code.

Comments

%c = when you want to print the character

%d = when you want to print the integer

int main()
{
    char example='a';
    printf("%d",example); //output   = 97  (ASCII value of 'a')
    printf("%c",example); //output = a (character having ASCII value of 97)  
    return 0;
}

in your statement

printf("The ASCII value of %c = %d\n",i,i); 

%c = character which is assigned to ' i ' variable

%d = value/integer of 'i' variable( in this case ASCII value of variable ' i '  )

 )

 

Answer 1

It means that whatever value is stored in i (as binary in the memory) , print the value after converting it to character by using %c conversion specifier and then again print the value after converting it to integer by using %d conversion specifier.

 

A conversion specifier begins with a percent sign, and ends with one of the following output conversion characters. The most basic conversion specifiers simply use a percent sign and one of these characters, such as %d to print an integer. (Note that characters in the template string that are not part of a conversion specifier are printed as-is.)

http://www.crasseux.com/books/ctutorial/Formatted-output-conversion-specifiers.html