c programming

Question

output of the following program?

#include<stdio.h>
int main()
{
    char arr[10];
    arr = "world";
    printf("%s",arr);
    return 0;
}

Why compilation error in this program , explain briefly?

Comments

arr is name of array....therefore it can't be use as lvalue, due to this compilation error.

for removing that, combine these statements

 char arr[10];
 arr = "world";

as  char arr[10] = "world";

 

---

@ Shaik Masthan can you explain why https://ideone.com/GAMla3 is giving undesired o/p. while, https://ideone.com/dFqTs0 is working fine.

---

in first code..

1. char arr[10];

2. arr[10] = "world";

 

it is wrong... arr[10] is a character variable, so you have to give character, otherwise it will generate warning but not compilation error due to memory address which is return by string constant "world" looking as integer 

if your code is 

1. char arr[10];

2. arr[10] = 'w';

then you are making the index 10 of arr is character 'w'.... but note that you didn't initialize  the elements of arr (arr[0],arr[1],...) due to this you are getting garbage printing...

 

---

in second code, you written that

char arr[10] = "world"; ---> initializing the array ===> correctly print