After 3 passes the element 5 will be at its correct position.
It is given to us that the last element has to be taken as the pivot.
| 12 |
7 |
15 |
8 |
19 |
20 |
17 |
21 |
5 |
3 |
So 3 is the pivot .. After the first pass the element 3 will be at the correct position.
| 3 |
7 |
15 |
8 |
19 |
20 |
17 |
21 |
5 |
12 |
Now for the second pass the element 12 is pivot and it will come to its right position.
| 3 |
7 |
8 |
5 |
12 |
20 |
17 |
21 |
15 |
19 |
Now in the third pass the (7,8,5) and(20,17,21,15,19)will be sorted using the partition method and the quicksort method.
So when quicksort will be called on (7,8,5) 5 will act as pivot and it will be placed at its right position.
So after 3 passes 5 will come at its correct position .
After three passes the array will look like this:
| 3 |
5 |
8 |
7 |
12 |
17 |
15 |
19 |
20 |
21 |
