work book

Question

Let S be a stack with operations push, pop, top, empty. What is displayed after following segment of code executes .

                               for(i=1; i<=5; i++)

                               s.push(i);

                               while(!s.empty())

                               printf("%d", s.top());

ans with explanation

Comments

@soumya29 yes because its not s.pop()

@srestha it will be having overflow

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THANKU

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@arvin the while loop will execute infinite times but should we call the final answer as Stack Overflow? Because the contents of the stack will be fixed to 5,4,3,2,1. The while loop will print infinite times but the stack is not overflowing right?