c programming

Question

what wiill be the output?

#include<stdio.h>
void main()
{
    int x;
    int a[] = {1, 2, 3, 4};
    int *p = a;
    for(int i=0; i<=3; i++)
    {
        x = *(p+i);
        printf("%d ",x);
    }
    printf("\n");
    for(int i=0;i<=3; i++)
    {
        x= *(p-i);
        printf("%d ", x);
    }
}

Comments

 x= *(p-i);

p at base address only...... this statement looks as wild pointer 

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should'nt p be at last element of array

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no u are incrementing p but u are storing that value in x which is changing every time with loop.
so value of p reamins same
so answer should be.

1,2,3,4

1, garbage, garbage,garbage

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thanks i missed that point

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But in Dev C compiler, I am getting *(p-1) as 0 , not able to understand why 

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i too ran this on online compiler its coming 0. i think maybe because of some property or criteria. because we cannot track *(p-1) .

Answer 1

The output should be -->

1 2 3 4

1 garbage-value garbage-value garbage-value