0 0 votes Consider a language L and its Complement L' and the statements with reference to L. S1: If L is undecidable then L'(i,e, L complement) may or may not be undecidable. Whether S1 is True of False. Please provide detailed explaination. Theory of Computation + – Dhananjay15 1.9k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
1 1 vote Undecidable means not recursive language ie RE but not Recursive and hence complement of RE but not Recursive always not recursive which is RE but not Recursive and hence Undecidable. So if L is Undecidable its complement is also Undecidable. Vikas Verma answered Aug 25, 2018 • edited Aug 25, 2018 by Vikas Verma Vikas Verma comment Share Follow See all 6 Comments 6 6 Comments reply Show 3 previous comments Vikas Verma commented Aug 25, 2018 reply Follow flag See, decidable languages are recursive languages. Hence Undecidable languages will be not recursive which is recursively enumerable but not Recursive. So complement of recursively enumerable languages will be either recursive enumerable or not even recursively enumerable and in both the cases it remains to be Undecidable. 1 1 replyShare Dhananjay15 commented Aug 25, 2018 reply Follow flag Thanks bro 0 0 replyShare Vikas Verma commented Aug 25, 2018 reply Follow flag Any day, man! 1 1 replyShare Please log in or register to add a comment.