static and dynamic scoping closed

Question

can anyone explain by using static and dynamic programing ? what will be output for static and dynamic?

   #include<stdio.h>
int x=10;
void part1(int *a)
{
*a+=x++;
printf("%d",*a);
}
void part2(int *b)
{
static x=15;
*b=*b*x;
part1(&x);
printf("%d",x);
}
void main(){
part2(&x);
part1(&x);
}

Comments

where is the program?

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added the problem..

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for learning the concept, that question is not good.

https://gateoverflow.in/241093/made-easy

Answer 1

by static scoping ans is 31,150