0 0 votes Consider the following statements 1. Decomposition of a relation into BCNF may not be lossless. 2. If R and S are two relations in BCNF the natural join of R and S is also in BCNF. which of the following is correct ? a) only 1 b) only 2 c) Both 1 and 2 d) None of these I have doubt in first option..please exlain.. Databases + – Siddharth Bhardawaj 2.1k views answer comment Share Follow Print See all 15 Comments 15 15 Comments reply Show 12 previous comments Shaik Masthan commented Sep 25, 2018 reply Follow flag @himgta if you want you can have a loss-less decomposition always, but note that every decomposition of BCNF doesn't need not to satisfy Lossless property. R(A,B,C,D) with FD set ={AB → D, C → AD} i want to decompose it in R1(A,B,D) R2(A,C,D), it is in BCNF and Dependency Preservation but lossy R1(A,B,D) R2(A,C,D), and R3(B,C) ===> BCNF, DP and Loss-less 0 0 replyShare Prateek Raghuvanshi commented Sep 25, 2018 reply Follow flag @ Shaik Masthan but at least one decomposition of that relation into BCNF always be lossless ,not any particular given decomposition. 0 0 replyShare Shaik Masthan commented Sep 26, 2018 reply Follow flag @Prateek Raghuvanshi yes brother, i am also conveyed that one only. 0 0 replyShare Please log in or register to add a comment.