0 0 votes Why P1 is still running after 2ms, shouldn't P2 get the cpu burst? In the video they said that are are no processes present other than P1 when the timer interrupts after 2 time slices. Isn't the gantt chart wrong. What i am missing here, can anyone explain it right? Operating System round-robin-scheduling + – himanshu6398 1.6k views answer comment Share Follow Print See all 9 Comments 9 9 Comments reply Show 6 previous comments himanshu6398 commented Oct 13, 2018 reply Follow flag okk.. i think im getting it.. P1 is already there first at t=2, but i think i've seen examples like this where the other processes are scheduled first.. dont know for sure. can i ask for the source of this implementation. And thank you so much for replying and clearing doubts. 0 0 replyShare Shaik Masthan commented Oct 13, 2018 reply Follow flag implementation defned means, while writing program of OS, the programmer write it. 0 0 replyShare himanshu6398 commented Oct 13, 2018 reply Follow flag okk 0 0 replyShare Please log in or register to add a comment.