0 0 votes closed with the note: Duplicate Computer Networks + – garimanand 2.1k views comment Share Follow Print See all 18 Comments 18 18 Comments reply Show 15 previous comments garimanand commented Oct 25, 2018 reply Follow flag solution by Made easy 0 0 replyShare Utkarsh Joshi commented Oct 25, 2018 i reshown by Subarna Das Oct 25, 2018 reply Follow flag they considered sa da and checksum as redundunt info! I don't think its correct way of doing it! 0 0 replyShare kavya kamish upadhya commented Jan 4, 2019 reply Follow flag because it is Ethernet frame so, They took 6B mac SA, 6B DA, 2B length field and 4B CRC So all redundant data would be 6+6+2+4=18B 0 0 replyShare Please log in or register to add a comment.
