there are 16 bits in the identification number space of an IPV4 datagram
since it is said the lifetime of a packet is 10 sec. So in order to prevent wrap around, at max we can send 216 packets in 10seconds, i.e. in 1 sec, we can send 216/10 packets.
length of a packet is given as 1024B. So in 1 sec, we can send 216 * 1024/10 Bytes. So in 1 sec, we can send 6.4MB. So maximum data rate that is possible is 6.4MBps= (6.4*8)Mbps= 51.2Mbps.
What is the answer for this?