1 1 vote Why can't I get answer by using formulae Window size = 1+2a..... Station A uses 32 byte packets to transmit messa ges to station B using sliding window protocol. The round trip delay between A and B is 40 milliseconds and the bottleneck bandwidth on the path between A and B is 64 kbps. The optimal window size of A is ______ 20 10 30 40 Computer Networks sliding-window computer-networks + – Fida 3.3k views answer comment Share Follow Print See all 17 Comments 17 17 Comments reply Show 14 previous comments Gurdeep Saini commented Nov 14, 2018 reply Follow flag photo icon is rounded 0 0 replyShare Shubham Aggarwal commented Nov 14, 2018 reply Follow flag @Gurdeep Saini answer may be wrong in test series not blindly depend on the answer given in test series. 0 0 replyShare Gurdeep Saini commented Nov 14, 2018 reply Follow flag @fida already sollved question let him updoad the pic 0 0 replyShare Please log in or register to add a comment.
1 1 vote Bottleneck bandwidth = 64 kbps=64x103 bps Round trip delay = 40 ms =40x10-3 sec Total data 40x64x103 x10-3 = bits = 40x64 /8 bytes =320 bytes. 1 packet size = 32 byte No. of packets 320/32 = 10 Hence (2 ) is the ans Shubham Aggarwal answered Nov 14, 2018 Shubham Aggarwal comment Share Follow See 1 comment 1 1 comment reply Fida commented Nov 14, 2018 reply Follow flag I can't using mobile website..it is asking for url soesometh 0 0 replyShare Please log in or register to add a comment.
