Why can't I get answer by using formulae
Window size = 1+2a.....
Station A uses 32 byte packets to transmit messa
ges to station B using sliding window protocol. The round trip delay between A and B is 40 milliseconds and the bottleneck bandwidth on the path between A and B is 64 kbps. The optimal window size of A is ______
photo icon is rounded
Bottleneck bandwidth = 64 kbps=64x103 bps
Round trip delay = 40 ms =40x10-3 sec
Total data 40x64x103 x10-3 = bits = 40x64 /8 bytes =320 bytes.
1 packet size = 32 byte
No. of packets 320/32 = 10
Hence (2 ) is the ans
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