1 votes 1 votes An organization is granted the block 130.56.0.0/16. The administrator wants to create 1024 subnets. Find the first and last addresses in subnet 3. Meenakshi Sharma asked Nov 16, 2018 Meenakshi Sharma 942 views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Soumya Tiwari commented Nov 16, 2018 reply Follow Share 130.56.0.128/26 and 130.56.0.191/26...?? 3 votes 3 votes himgta commented Nov 16, 2018 reply Follow Share Can u post the complete solution? 0 votes 0 votes Manas Mishra commented Nov 16, 2018 reply Follow Share 130.56.0.0/16. , as need 1024 subnest so we will have to take 10 bits from HID as 2^10 = 1024.. now , third adrees will be from .... 130.56.0.10000000/26 to 130.56.0.10111111/26 = 130.56.0.128/26 to 130.56.0.191/26 2 votes 2 votes Meenakshi Sharma commented Nov 17, 2018 reply Follow Share third subnet (not third address) 0 votes 0 votes Manas Mishra commented Nov 17, 2018 reply Follow Share o sorry typo mistake 0 votes 0 votes Please log in or register to add a comment.
