Programming

Question

Comments

It's concurrent execution right...

Perform P1 condition check and preempt

Perform P2 condition check and execute y=y+1-->y=2

execute p1 twice -> x=2

EXECUTE Z=(x!=y) --> z = false so p2 loop breaks --> p2 is terminated

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let's suppose after p2 condition check.. p1's loop is run 3 times then x=2 and y is y=1. then p1's while condition is violating means p1 is terminating too. @Hemanth_13

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Noo need of that just run P1 first then in the 2nd iteration condition will fail and P1 has to terminate.

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i think both of them should terminate