C PROGRAM

Question

What will be the output of the following C program?

#define b ++a

void main()

{

     char a=2689;

    printf(“%d”, b);

}

Comments

binary of $a = 0000101010000010$, as a is $char$ only the first $8$ bits are used.

$a=10000010$

b = ++a = 10000011 = -126

printf(“%d”, b);

should print $-126$.

Correct me if i'm wrong

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hmmShobhit Joshi u r correct i think

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right.

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@Shobhit Joshi

why u taken a as 16 bit?

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I think we can represent 2689 in binary as 101010000010, but as a is char so it will store only first(from the right side) 8 bit.

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@Shobhit Joshi sir,  I am unable to understand the logic ?

please provide detailed explanation behind the concept!! 

Answer 1

-126 due to wrap around