#c programming

Question

#include <stdio.h>
int cou=0;
int cal(int a,int b){
    int c;
    cou++;
    if(b==3)
    return(a*a*a);
    else{
        c=cal(a,b/3);
        return(c*c*c);
       
    }
}
int main() {
   int d= cal(4,81);
   printf("%d",d);
    
    return 0;
}

Comments

if b is multiple of 3, then function simply returns a$^b$