for i <--- 1 to n for j <---- 1 to n/2 X = X + 1 (i and j both are incrementing by 1) Outer runs for n times and inner for n/2 So will it be n(n/2) => O(n^2) times...

What is time complexity of following code : int count = 0; for (int i = N; i > 0; i /= 2) { for (int j = 0; j < i; j++) { count += 1; } } Please give ans with explanation ? Thankyou

Consider the following c fragment : void DAA(n) { int i,j,k,x=0; for (i=1 ; i <=n ; i++) for (j=1 ; j <= i * i ; j++) { if ( j mod i == 0 ) for ( k = 1 ; k <= j ; k++) x=x+10; } } Find the time complexity of above code in terms of input size n.