Z-> Y is not satisfied as when Z = 4, Y has values 8 as well as 4. So, (A) is False.
YZ and Y are unique and hence FDs in (B) are trivially satisfied.
X->Z is not satisfied as when X=2, Z can have 4 as well as 6. So, (C) is false.
XZ -> Y is not satisfied as when XZ = {2,6}, Y can have 10 as well as 12. So, D is false.