ds and programming

Question

when i printing x it is giving 0 but when comparing x with 5 ,it executing else part ,means condition fail ,why ??

#include <stdio.h>

int main(void) {
int x;
     if(x=(printf("Hello")) != 5)
      printf("Hello");
   else
      printf("World \n");
     printf("%d  \n",x);
    return 0;
}

https://ideone.com/NJSj2i

Comments

Your forgot to put parenthesis.

what is happening in the above code :

printf is returning 5 which is being compared with 5 before storing the value in variable x because the precedency of != is more than =. after comparing 5 != 5, which is false, it will ruturn 0. This 0 is stored in the variable x.

 

int main()
{
    int x = 10;
     if((x=(printf("Hello"))) != 5)
      printf("Hello");
   else
      printf("World \n");
     printf("%d  \n",x);

    return 0;
}

---

thanks @OneZero   you really pointed out the mistake

edited comment

---

@Gurdeep Saini

Its OneZero :P

Answer 1

yes as printf returns number of characters it print so here printf("Hello") will return 5 and the condition 5!=5 become false due to which x will get 0.Change "HELLO" with "HY" 2!=5 true hence x=1