Register

Array

1,518 views
1 votes
1 votes

Tell me the difference :
&(arr+1)   and    &arr+1 

User Avatar

2 Answers

5 votes
5 votes
The name of the array gives the address of the 0th element. So if we add 1 to the name of the array it will contain the address of the next element.

But if we look at the other one "&arr" this gives the address of the entire array and now when we increment it by one it will contain the address of the second array of same size.
• edited by
User Avatar
Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

803
views
1 answers
0 votes
aditi19 asked Sep 13, 2018
803 views
2D Array using Double pointers
what is wrong with this code? It shows segmentation fault#include<stdio.h>#include<stdlib.h>void main(){ int i,j,count=1; int **a=(int**)malloc(3*sizeof(int*)); for(i=0; i<3; ... ("%d ",a[i][j]); } printf("\n"); }}
User Avatar
644
views
1 answers
0 votes
shivam sharma 5 asked Aug 28, 2018
644 views
array long with pointers
give the complete solution with explanationint main(){ int arr [2] [2] [2] = {10,2,3,4,5,6,7,8}; int *p, *q; p = &arr[1] [1] [1]; q = (int*) arr; printf("%d ,%d \n",*p ,*q); return 0;}
User Avatar
5.8k
views
8 answers
13 votes
Na462 asked Aug 22, 2018
5,805 views
Two dimensional array
Consider a 2 dimensional array A[40...95,40...95] in lower triangular matrix representation. The size of each element of array is 1 Byte.If array is implemented in memory ... base address as 1000,the address of A[66][50] is .....Ans. 1361
User Avatar
1.1k
views
1 answers
1 votes
Balaji Jegan asked Jun 27, 2018
1,057 views
Multi-dimensional Array
Can anyone please verify whether I have calculated the addresses correctly or not?
User Avatar
Link Copied!