0 0 votes Suppose Host A wants to send a large file to Host B. The path from Host A to Host B has three links, of rates R1 = 500 kbps, R2 = 2 Mbps, and R3 = 1 Mbps. Assuming no other traffic in the network, what is the throughput for the file transfer? Suppose the file is 4 million bytes. Dividing the file size by the throughput, roughly how long will it take to transfer the file to Host B? Repeat (a) and (b), but now with R2 reduced to 100 kbps. Computer Networks computer-networks kurose-and-ross network-layer network-flow + – ajaysoni1924 1.3k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes a)Throughput for file transfer $= 500\text{kbps}$ b) Time taken for transfer the file to host $\text B=\frac{(4\times {10}^6)\times 8}{(500\times{10}^3} = 64\; \text{seconds}$ c)For R2, Throughput = $100\text{kbps}$, Time taken for transfer$ = \;\frac{4\times{10}^6\times 8}{100\times{10}^3}= 320\; \text{seconds}$ `JEET answered Oct 21, 2019 `JEET comment Share Follow 0 reply Please log in or register to add a comment.