Suppose two hosts, A and B, are separated by 20,000 kilometers and are connected by a direct link of R = 2 Mbps. Suppose the propagation speed over the link is $2.5×10^8$meters/sec.
You can calculate from Part b), which says that 20 packets each of size 40,000 bits.
a) 400.16 sec
b) 403.2 sec
c) Part b) is Stop and Wait