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The area of the shaded region in the following figure (all the arcs are circular) is

1. $\pi$
2. $2 \pi$
3. $3 \pi$
4. $\frac{9}{8} \pi$

recategorized | 20 views

+1 vote

It's like semicircle of radius 1 unit is cut from the semicircle of radius 2 units and joined upside down to the semicircle of 2 units. So, the shaded area will be area of the semicircle with 2 units.

Hence, Shaded Area   $= \frac{1}{2}\cdot\pi \cdot (2^2) = 2 \pi$

by Active (2k points)