0 0 votes The area of the shaded region in the following figure (all the arcs are circular) is $\pi$ $2 \pi$ $3 \pi$ $\frac{9}{8} \pi$ Quantitative Aptitude isi2017-dcg quantitative-aptitude geometry area + – gatecse 780 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
4 4 votes Correct Answer - Option (B) It's like semicircle of radius 1 unit is cut from the semicircle of radius 2 units and joined upside down to the semicircle of 2 units. So, the shaded area will be area of the semicircle with 2 units. Hence, Shaded Area $ = \frac{1}{2}\cdot\pi \cdot (2^2) = 2 \pi$ txds answered Sep 21, 2019 txds comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes yes the area of the shaded portion will be 2 π as the area of the big semicircle is 2 π and π/2 has been cut in the RHS of the big semi circle and appended in the LHS side below. Hence the area reamins the same which is equal to 2 π.and the option B is correct. DIBAKAR MAJEE answered May 3, 2020 DIBAKAR MAJEE comment Share Follow 0 reply Please log in or register to add a comment.