1 1 vote The coefficient of $x^{2}$ in the product $(1+x)(1+2x)(1+3x)\cdots (1+10x)$ is $1320$ $1420$ $1120$ None of these Quantitative Aptitude isi2016-dcg quantitative-aptitude number-system + – gatecse 693 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
2 2 votes ignore multiplications that give $x^i$ where $i>2$ $(1+x)(1+2x)(1+3x)(1+4x)(1+5x)(1+6x)(1+7x)(1+8x)(1+9x)(1+10x)$ $=(1+3x+2x^2)(1+7x+12x^2)(1+11x+30x^2)(1+15x+56x^2)(1+19x+90x^2)$ $=(1+7x+12x^2+3x+21x^2+2x^2)(1+15x+56x^2+11x+165x^2+30x^2)(1+19x+90x^2)$ $=(1+10x+35x^2)(1+26x+251x^2)(1+19x+90x^2)$ $=(1+26x+251x^2 + 10x + 260x^2 +35x^2)(1+19x+90x^2)$ $=(1+ 36x+546x^2 )(1+19x+90x^2)$ $=(1+19x+90x^2+36x+684x^2 +546x^2)$ So the coeffecient of $x^2 = 90+684+546= 1320$ $\therefore$ Option $A.$ is correct.. Satbir answered Sep 21, 2019 Satbir comment Share Follow 0 reply Please log in or register to add a comment.