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If one root of a quadratic equation $ax^2+bx+c=0$ be equal to the $n^{th}$ power of the other, then

  1. $(ac)^{\frac{n}{n+1}} +b=0$
  2. $(ac)^{\frac{n+1}{n}} +b=0$
  3. $(ac^{n})^{\frac{1}{n+1}} +(a^nc)^{\frac{1}{n+1}}+b=0$
  4. $(ac^{\frac{1}{n+1}})^n +(a^{\frac{1}{n+1}}c)^{n+1}+b=0$
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Let (x-2)(x-4) =0 equations where a=1 b=-6 c=8 n=2 root1=2 root2=4 options C satisfied answer

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