0 votes 0 votes If one root of a quadratic equation $ax^2+bx+c=0$ be equal to the $n^{th}$ power of the other, then $(ac)^{\frac{n}{n+1}} +b=0$ $(ac)^{\frac{n+1}{n}} +b=0$ $(ac^{n})^{\frac{1}{n+1}} +(a^nc)^{\frac{1}{n+1}}+b=0$ $(ac^{\frac{1}{n+1}})^n +(a^{\frac{1}{n+1}}c)^{n+1}+b=0$ Quantitative Aptitude isi2015-dcg quantitative-aptitude quadratic-equations roots + – gatecse asked Sep 18, 2019 recategorized Nov 14, 2019 by Lakshman Bhaiya gatecse 252 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Let (x-2)(x-4) =0 equations where a=1 b=-6 c=8 n=2 root1=2 root2=4 options C satisfied answer amit166 answered Sep 20, 2019 amit166 comment Share Follow See all 0 reply Please log in or register to add a comment.