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How many bits are required to encode all twenty six letters, ten symbols, and ten numerals?

1. $5$
2. $6$
3. $7$
4. $46$

26 letters + 10 symbols + 10 numerals = 46
any binary code is represented in powers of 2

5 BIT=2^5=32

6 BIT=2 ^6 =64

7 BIT=2^7=128

In 6 bit  is sufficient we can can represent the 46 thing uniquely..

option should be B.

In 6 bit  is sufficient we can can represent the 46 thing uniquely..

option -- B

1
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