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It's always best to turn the variables into constants in such questions.

Let there be 2 words of 3 bits each.

Each word could be: 

  • 000
  • 001
  • 010
  • 011
  • 100
  • 101
  • 110
  • 111

There are 2 such words.

Now Option A would suggest there are $2*8=16$ states.

Option B would suggest there are $2^{5}=32$ states.

Option C would suggest there are $2^{6}=64$ states.

Option D would suggest there are $5$ states. This can be eliminated straight as Just 1 word alone has 8 states.

 

Total states could be: Word 1 is $000$ and Word 2 could be $000$ or $001$ or...or $111$

Hence, do a cross product.

Word 1 Word 2
000 000
001 001
010 010
011 011
100 100
101 101
110 110
111 111

You'll get $8*8=64$ which is Option C

Answer:

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