It's always best to turn the variables into constants in such questions.
Let there be 2 words of 3 bits each.
Each word could be:
- 000
- 001
- 010
- 011
- 100
- 101
- 110
- 111
There are 2 such words.
Now Option A would suggest there are $2*8=16$ states.
Option B would suggest there are $2^{5}=32$ states.
Option C would suggest there are $2^{6}=64$ states.
Option D would suggest there are $5$ states. This can be eliminated straight as Just 1 word alone has 8 states.
Total states could be: Word 1 is $000$ and Word 2 could be $000$ or $001$ or...or $111$
Hence, do a cross product.
Word 1 |
Word 2 |
000 |
000 |
001 |
001 |
010 |
010 |
011 |
011 |
100 |
100 |
101 |
101 |
110 |
110 |
111 |
111 |
You'll get $8*8=64$ which is Option C