GATE CSE 2012 | Question: 3

Question

What will be the output of the following C program segment?

 char inChar = 'A';
    switch ( inChar ) {
       case 'A' : printf ("Choice A \ n");
       case 'B' :
       case 'C' : printf ("Choice B");
       case 'D' :
       case 'E' :
       default : printf ("No Choice"); 
    }

• A. No Choice
• B. Choice A
• C. Choice A
  Choice B No Choice
• D. Program gives no output as it is erroneous

Comments

@Bhaskar_Pallela No, in the question they have given "\ n" space should not be present.

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@Bhaskar_Pallela Char is an integeral type in C, so it can be used as switch argument and case label value.

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c

Answer 1

There is a `space` in between the `\` and `n` in the printf of case ‘A’ and also no space after the printf for case ‘C’ in the original question (see-Q-no.-3). Due to this “Marks to All” was done.

Lets assume no space for “\n” in the printf for case ‘A’ and there is a space at the end of printf of case ‘C’.

When a case of a switch is matched, execution continues from the matched case until a “break” is encountered (any intermediate case labels simply gets ignored).

So, output of the given program is:

Choice A
Choice B No Choice 

Option C.

Comments

If the q had 

  case 'A' : printf ("Choice A \n");

Then the Output would be :-

Choice A 
Choice BNo Choice

Even this is not present in Option C.

Edit: Ok, there is a space after Choice B. So in new question, ans is Option C.

Thanks @Pranavpurkar for pointing it out. 

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@Abhrajyoti00

are you considering the space between (as it  is not the same in options)

1. Choice BNo Choice

B and N?

 

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for the given question what actually it prints

Answer 2

There is no break statement in  any case . If a case doesn’t contain break, then all the subsequent cases are executed until a break statement is found. That is why everything inside the switch is printed.

so ans is C

Answer 3

Syntax:

1. switch(expression)
2. {
3. case constant-exp1 : statements; break;
4. case constant-exp2: statements; break;
5. default: statements;
6. }

In switch case, the break statement is used to terminate the switch case. Basically it is used to execute the statements of a single case statement. If no break appears, the flow of control will fall through all the subsequent cases until a break is reached or the closing curly brace ‘}’ is reached.

In above , switch case don't have break statement , 

1. If inChar='A'  , flow control will execute all statements after Case A: till switch case end (in case any break states occurs between statement , it will terminated at the point but in above example we don't have any break statement, so whole switch block will execute).

Output : Choice A
               Choice B No Choice

In case if inChar='C' then output will be  Choice B No Choice.

it's not necessary that we should always add break statement for each cases in switch, including break statement in switch case is based on our requirement.

Answer is C

Answer 4

Answer: Option C

There is no break statement after case A, if there is no break statement then it will execute all the subsequent cases. So it will execute all those print statements. Hence option C. 

To know more about Switch statement refer this: https://www.geeksforgeeks.org/interesting-facts-about-switch-statement-in-c/ it will clear all the doubts.

 

Answer 5

In switch case if a condition contains a break that case is being executed than the switch case will terminate

 switch ( inChar ) {

       case 'A' : printf ("Choice A \ n");

WE CAN SEE HERE THAT there is no break statement inside case though in char is A
 BT THIS STATEMENT WILL NOT TERMINATE as it doesnt contain break
here output will be Choice A

so now case B is being executed

       case 'B'

here there is nothing inside so now case C will execute

       case 'C' : printf ("Choice B");
noe case C will execute and Choice B is printed
ALSO POINT TO BE NOTED AS DUE TO /n IN case A the curser had moved to nct line
so “Choice B” will be executed in next line.

now case D will be executed

       case 'D' :
it also doesnt contain any statement so  now case E will execute
which also contain no statement

       case 'E' :

so in last default will also execute

       default : printf ("No Choice");

and No Choice will be printed . 

AND THIS LEAD TO END OF SWITCH CASE AND HERE THERE WAS NO break statement so all cases got executed 

 

SO FINAL OUTPUT WILL BE

Choice A

Choice B No Choice

 

Answer 6

C , it matches with case a then falls through till it encounters a break statement.