Given that, $R \quad S \quad K$
Time$: \qquad5 \quad 10 \quad x\quad $ (days)
Total work $: LCM(5,10,x) = 50x$ unit.
Efficiency$: 10x \quad 5x \quad 50$
We know that, $\text{Total work = Efficiency $\times$ Time}$
$\implies 50x = (15x + 50) \times 2$
$\implies 50x = 30x + 100$
$\implies 20x = 100$
$\implies x = 5$ days.
So, the correct answer is $(A).$