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CMI-2019-DataScience-A: 2

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If we think practically...

See..
P(A union B) => All the elements that are either in A or in B or in Both...!! = 0.7
So, P(everything except A or B) = 1 - 0.7 = 0.3
P(A union B') => P(B') = P(Everything except B) = 0.9...!!

So, from here, we can say that...
P(A) = P(everything except B) - P(everything except A or B) = P(only A) = 0.9 - 0.3 = 0.6

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