UGC NET CSE | December 2019 | Part 2 | Question: 65

Question

Let the population of chromosomes in genetic algorithm is represented in terms of binary number. The strength of fitness of a chromosome in decimal form, $x$, is given by

$S f(x) = \dfrac{f(x)}{\Sigma f(x)}$ where $f(x) = x^2$

The population is given by $P$ where:

$P=\{(01101, (11000), (01000), (10011)\}$

The strength of fitness of chromosome $(11000)$ is ________

• A. $24$
• B. $576$
• C. $14.4$
• D. $49.2$

Comments

$49.2$?

---

http://www.eis.mdx.ac.uk/staffpages/rvb/teaching/BIS4435/lab-09-sol.pdf

---

https://www.massey.ac.nz/~nhreyes/MASSEY/159741/Lectures/Lecture%20-%20Genetic%20Algorithm%20-%20Part%201.pdf

---

In this question  given that                                                                                                                                                    

 The population of chromosome in genetic algorithm is represent in term of binary number.

    The strength of fitness of chromosome in decimal form of x     

   The population is given by  P={(01101),(11000),(01000),(10011)}

	P	X -Value	f(x)=X^2
	01101	13	169
	11000	24	576
	01000	8	64
	10011	19	361
Sum			1170

 S f(x)= f(x)/ Σ f(x)                 where f(x)=x^2

Strength of fitness of chromosome (11000) is

= f(11000) /  f(01101)+f(11000)+f(01000)+f(10011)

= 576/169+576+64+361

=576/1170

=0.492

so option 4 ) 49.2 is correct

 

Answer 1

D