Since 193.1.2.3 is a class C address and in class c address bits used for Network ID are 24 bits
The given subnet mask is 255.255.255.240 = 11111111.11111111.11111111.11110000
Number of bits used for subnetting are 4
So Number of subnets = 2 Power ( Bits used for Subneting) = 16
Last 4 bits 0000 are used fir host
Number of hosts per subnet= 2 Pow( Bits used for Hosts ) - 2
= 16 – 2 = 14