0 votes 0 votes Let $\int ^{2}_{1} e^{x^{2}} dx = a$. Then the value of $\int ^{e^{4}}_{e} \sqrt{\log_{e} x} dx$ is $e^{4} - a$ $2e^{4} - a$ $e^{4} - e – 4a$ $2e^{4} - e – a$ Others isi2020-mma + – admin asked Jul 23, 2022 • edited Aug 7, 2022 by Lakshman Bhaiya admin 313 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.