| 1 |
0 |
1 |
P4 |
1 |
P2 |
P1 |
| 7 |
6 |
5 |
4 |
3 |
2 |
1 |
We have to find even parity bit Value for the possition P1, P2, P4( Parity is 2 Power N, where N=0,1,2,...N){1,2,4,8,16,32,....N}
2power r >m+r+1; where m=data bit, r=redundant / pairty bit in number of
Parity bit position: 1,2,4
Position:(based on parity )
3 = 1+2
5=1+4
6=2+4
7=1+2+4
Now P4---->
| 5 |
6 |
7 |
|
| 1 |
0 |
1 |
even then P4=0 |
P2---->
| 3 |
6 |
7 |
|
| 1 |
0 |
1 |
even then P2=0 |
P1----->
| 3 |
5 |
7 |
|
| 1 |
1 |
1 |
odd then P1=0 |
Then The Value of P1=1, P2= 0, P4=0 ,Apply this value in the First table
The Ans is 1010101 (B)
