I got the Answer **0110011 **- Even Parity

**1011011 **- Odd Parity

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1 | 0 | 1 | P4 | 1 | P2 | P1 |

7 | 6 | 5 | 4 | 3 | 2 | 1 |

We have to find even parity bit Value for the possition P1, P2, P4( Parity is 2 Power N, where N=0,1,2,...N){1,2,4,8,16,32,....N}

2power r >m+r+1; where m=data bit, r=redundant / pairty bit in number of

Parity bit position: 1,2,4

Position:(based on parity )

3 = 1+2

5=1+4

6=2+4

7=1+2+4

Now P4---->

5 | 6 | 7 | |

1 | 0 | 1 | even then P4=0 |

P2---->

3 | 6 | 7 | |

1 | 0 | 1 | even then P2=0 |

P1----->

3 | 5 | 7 | |

1 | 1 | 1 | odd then P1=0 |

Then The Value of P1=1, P2= 0, P4=0 ,Apply this value in the First table

The Ans is 1010101 (B)

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