UGCNET CSE December 2022: 33

Question

Given Ethernet address $010110100001000101010101000110001010101000001111$ in binary, what is the address in hexadecimal notation?

• A. $5 \mathrm{~A}: 88: \mathrm{AA}: 18: 55: \mathrm{F} 0$
• B. $5 \mathrm{~A}: 81: \mathrm{BA}: 81: \mathrm{AA}: 08$
• C. $5 \mathrm{~A}: 18: 5 \mathrm{~A}: 18: 55: 0 \mathrm{~F}$
• D. $5 \mathrm{~A}: 11: 55: 18: \mathrm{AA}: 0 \mathrm{~F}$

(Option $1 [39429]) 1$
(Option $2 [39430]) 2$
(Option $3 [39431]) 3$
(Option $4 [39432]) 4$

Answer Given by Candidate : $4$

Answer 1

while decimal to hexadecimal conversion the numbers form $0-15$ are represented as $0,1,2….9,A,B,C,D,E,F$ forms and each binary digits is grouped as 4 bits. 

So for given Ethernet address $01011010:\ 00010001:\ 01010101 :\ 00011000:\ 10101010 :\ 00001111$ hexadecimal notation is:

• $0101\ 1010=5A$
• $0001\ 0001=11$
• $0101\ 0101=55$
• $0001\ 1000=18$
• $1010\ 1010=AA$
• $0000\ 1111=0F$

Therefore correct hexadecimal representation of the given Ethernet address is $5A:11:55:18:AA:0F$

Option (4) is correct.